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x^2-0.35x-46200=0
a = 1; b = -0.35; c = -46200;
Δ = b2-4ac
Δ = -0.352-4·1·(-46200)
Δ = 184800.1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.35)-\sqrt{184800.1225}}{2*1}=\frac{0.35-\sqrt{184800.1225}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.35)+\sqrt{184800.1225}}{2*1}=\frac{0.35+\sqrt{184800.1225}}{2} $
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